6b^2-4b=8b+2b

Solution for 6b^2-4b=8b+2b equation:

6b^2-4b=8b+2b

We move all terms to the left:

6b^2-4b-(8b+2b)=0

We add all the numbers together, and all the variables

6b^2-4b-(+10b)=0

We get rid of parentheses

6b^2-4b-10b=0

We add all the numbers together, and all the variables

6b^2-14b=0

a = 6; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·6·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*6}=\frac{0}{12}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*6}=\frac{28}{12}
=2+1/3
$